0=x^2-29x+108

Solution for 0=x^2-29x+108 equation:

0=x^2-29x+108

We move all terms to the left:

0-(x^2-29x+108)=0

We add all the numbers together, and all the variables

-(x^2-29x+108)=0

We get rid of parentheses

-x^2+29x-108=0

We add all the numbers together, and all the variables

-1x^2+29x-108=0

a = -1; b = 29; c = -108;
Δ = b2-4ac
Δ = 292-4·(-1)·(-108)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{409}}{2*-1}=\frac{-29-\sqrt{409}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{409}}{2*-1}=\frac{-29+\sqrt{409}}{-2}
$